Nice linux command to ignore lots of files

I've been working with git from command line lately and in this particular project we have a folder to store cache files (we use other cache stores in production) which gets crowded really quickly and doing a git status was not pleasant at all, here is a screenshot from inside that folder (file/cache):

at the end of the list it would show the files I was interested in but still... A couple of minutes later I came up with this one liner to remove all of these files:

git status | egrep cache | tr -s ' ' | cut -d ' ' -f 2 | xargs git rm --cached $1;

Let me explain why it works, the first part (git status) runs the normal git status command but this one is cluttered with extra information, I just want the files that belong to the cache folder so a simple egrep cache filters the lines that do not contain the word "cache". Now, I wasn't sure if those were spaces or tab characters so to make it more universal I decided to remove duplicated spaces with tr -s ' ', it does not remove all spaces, just the duplicated ones so '    ' becomes ' '. The next part is the cut -d ' ' -f 2 which basically extracts the information from column 2, and finally pass that to git rm --cached 

Note that all of these commands are "glued" with the pipe character ( this one: | ) which takes the output from the previous command and passes it as a param to the next command.